7b^2=-168-70b

Solution for 7b^2=-168-70b equation:

7b^2=-168-70b

We move all terms to the left:

7b^2-(-168-70b)=0

We add all the numbers together, and all the variables

7b^2-(-70b-168)=0

We get rid of parentheses

7b^2+70b+168=0

a = 7; b = 70; c = +168;
Δ = b2-4ac
Δ = 702-4·7·168
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(70)-14}{2*7}=\frac{-84}{14}
=-6
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(70)+14}{2*7}=\frac{-56}{14}
=-4
$